Published by:
CGP EDU Academic Team
Published on: August 14, 2026
`Let h(x) = min.{x, x 2 } for every real number x. Then:
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, c and d)
= h(x) = 
Thus h is differentiable except possibly at x = 0,
1h ′ (0 + ) =
=
= 0
h ′ (0 – ) =
=
= 1
Hence h is not differentiable at x = 0. Similarly h ′ (1 + ) =1 and h ′ (1–) = 2. Also
h(x) = 0 = h(0) =
h(x) and
h(x) = 1 = h(1) =
h(x).
Hence h is a continuous function and is not differentiable at two values of x.
Conclusions can also be made by drawing graph of the
function h(x).
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